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0
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If $a \;>\;0$ and $b^2-4ac=0,$ then the curve $y=ax^2+bx+c$
(a) cuts the x-axis
(b) touches the x-axis and lies below it
(c) ties entirely above the x-axis
(d) touches the x-axis and lies above it
jeemain
eamcet
math
2011
q29
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asked
Sep 20, 2013
by
meena.p
edited
Dec 23, 2013
by
meenakshi.p
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1 Answer
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(d) touches the x-axis and lies above it
answered
Nov 7, 2013
by
pady_1
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