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Home  >>  EAMCET  >>  Mathematics
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If $\tan A $ and $\tan B$ are the roots of the quadratic equation $x^2-px+q=0,$ then $\sin^2 (A+B)$=

\[\begin {array} {1 1} (a)\;\frac{p^2}{p^2+q^2} & \quad (b)\;\frac{p^2}{(p+q)^2} \\ (c)\;1-\frac{p}{(1-q)^2} & \quad (d)\;\frac{p^2}{p^2+(1-q)^2} \end {array}\]

Can you answer this question?
 
 

1 Answer

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$(d)\;\frac{p^2}{p^2+(1-q)^2} $
answered Nov 7, 2013 by pady_1
 

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