logo

Ask Questions, Get Answers

X
 
Home  >>  EAMCET  >>  Mathematics

If $\tan A $ and $\tan B$ are the roots of the quadratic equation $x^2-px+q=0,$ then $\sin^2 (A+B)$=

\[\begin {array} {1 1} (a)\;\frac{p^2}{p^2+q^2} & \quad (b)\;\frac{p^2}{(p+q)^2} \\ (c)\;1-\frac{p}{(1-q)^2} & \quad (d)\;\frac{p^2}{p^2+(1-q)^2} \end {array}\]

Download clay6 mobile app

1 Answer

$(d)\;\frac{p^2}{p^2+(1-q)^2} $
answered Nov 7, 2013 by pady_1
 

Related questions

...