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How many moles of electrons weigh one kilogram?

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A)
Solution :
$1\;mole= 6.023 \times 10^{23}\;electron$
One electron weighs $9.108 \times 10^{-31}\;kg$
$\therefore 6.023 \times 10^{23}$ electrons weighs $6.023 \times 10^{23} \times 9.108 × 10^{−31} kg$
Now, one kg of electron contain $= 1/ 6.023 \times 10^{23} \times 9.108 \times 10^{-31}$
$\qquad= 1/9.108 \times 6.023 \times10^8$
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