# If $x$ is real, the value of $\large\frac{x^2-3x+4}{x^2+3x+4}$ lies in the interval

$\begin {array} {1 1} (a)\;\bigg[\frac{1}{3},3\bigg] & \quad (b)\;\bigg[\frac{1}{5},5 \bigg] \\ (c)\;\bigg[\frac{1}{6},6\bigg] & \quad (d)\;\bigg[\frac{1}{7},7\bigg] \end {array}$

$(d)\;\bigg[\frac{1}{7},7\bigg]$
answered Nov 7, 2013 by