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$A(\alpha, \beta)=\begin {bmatrix} \cos \alpha & \sin \alpha & 0 \\ -\sin \alpha & \cos \alpha & 0 \\ 0 & 0 & e^{\beta} \end{bmatrix} => [A(\alpha, \beta)]^{-1}=$

\[\begin {array} {1 1} (a)\;A(-\alpha,\beta) & \quad (b)\;A(- \alpha, -\beta) \\ (c)\;A(\alpha, -\beta) & \quad (d)\;A(\alpha, \beta) \end {array}\]

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1 Answer

$(b)\;A(- \alpha, -\beta)$
answered Nov 7, 2013 by pady_1
 

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