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$A=\begin{bmatrix} 1 & 0 & 1\\ 0 & 1 & 1 \\ 0 & 1 & 0\end{bmatrix} \;=>\;A^2-2A=$

\[\begin {array} {1 1} (a)\;A^{-1} & \quad (b)\;-A^{-1} \\ (c)\;I & \quad (d)\;-I \end {array}\]

1 Answer

(b) $-A^{-1}$
answered Nov 7, 2013 by pady_1
 

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