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Let $z=a-\large\frac{i}{2};$$ \alpha \; \in IR.$ Then $|i+z|^2-|i-z|^2=$

\[\begin {array} {1 1} (a)\;2 & \quad (b)\;-2 \\ (c)\;4 & \quad (d)\;-4 \end {array}\]

1 Answer

(b) -2
answered Nov 7, 2013 by pady_1
 

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