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# What is molarity of a solution contain $5.84\;gms$ of Nacl in 200 ml of solution ?

$(a)\;0.5\;m \\ (b)\;25\;m \\(c)\;90\;m \\(d)\;0.1\;m$

Number of the moles of NaCl $=0.1$
Molality =$\large\frac{moles}{litre}$
Volume of solution in litre $\large\frac{200}{1000}$$=0.2 Molarity of the solution = \large\frac{0.1}{0.2}=\frac{1 \times 10^{-1}}{2 \times 10^{-1}}$$=0.5\;m$