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Home  >>  EAMCET  >>  Mathematics
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$(\tan ^{-1}x)^2+(\cot ^{-1}x)^2=\large\frac{5 \pi^2}{8}$$=>x=$

\[\begin {array} {1 1} (a)\;-1 & \quad (b)\;1 \\ (c)\;0 & \quad (d)\;\pi \sqrt {\frac{5}{8}} \end {array}\]
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$ (a)\;-1$
answered Nov 7, 2013 by pady_1
 
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