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If $|\bar {a}|=1$,$ |\bar {b}|=2$ and the angle between $\bar {a} $ and $\bar {b}$ is $120^{\circ},$ then $\{(\bar {a}+ 3 \bar {b}) \times (3 \bar {a}-\bar {b})\}^2=$

\[\begin {array} {1 1} (a)\;425 & \quad (b)\;375 \\ (c)\;325 & \quad (d)\;300 \end {array}\]

1 Answer

(d) 300
answered Nov 7, 2013 by pady_1
 

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