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Let $\bar {v}=2 \bar{i}+\bar {j}-\bar {k}$ and $\bar {w}=\bar {i}+3 \bar{k}$. If $ \bar u$ is any unit vector then the maximum value of the scalar triple product $(\bar {u} \; \bar {v}\; \bar {w})$ is

\[\begin {array} {1 1} (a)\;1 & \quad (b)\;\sqrt {10}+\sqrt {6} \\ (c)\;\sqrt {59} & \quad (d)\;\sqrt {60} \end {array}\]

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$ (c)\;\sqrt {59}$
answered Nov 7, 2013 by pady_1

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