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Seven white balls and three black balls are randomly arranged in a row. The probability that no two black balls are placed adjacently is
\[\begin {array} {1 1} (a)\;\frac{1}{2} & \quad (b)\;\frac{7}{15} \\ (c)\;\frac{2}{15} & \quad (d)\;\frac{1}{3} \end {array}\]
jeemain
eamcet
math
2011
q56
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Sep 23, 2013
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