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If the lines $3x+4y-14=0$ and $6x+8y+7=0$ are both tangents to a circle, then its radius is

$\begin {array} {1 1} (a)\;7 & \quad (b)\;\frac{7}{2} \\ (c)\;\frac{7}{4} & \quad (d)\;\frac{7}{6} \end {array}$

$(c)\;\frac{7}{4}$

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