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Home  >>  EAMCET  >>  Mathematics
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The radius of the circle given by $x^2+y^2+z^2+2x-2y-4z-19=0=x+2y+2z+7,$ is

\[\begin {array} {1 1} (a)\;4 & \quad (b)\;3 \\ (c)\;2 & \quad (d)\;1 \end {array}\]
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(b) 3
answered Nov 7, 2013 by pady_1
 
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