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If $200 \;MeV$ of energy is released in the fission of one nucleus of $^{235}_{92} U$, the number of nuclei that must undergo fission to release an energy of $1000\;J$ is :

\[\begin {array} {1 1} (a)\;3.125 \times 10^{13} & \quad (b)\;6.25 \times 10^{13} \\ (c)\;12.5 \times 10^{13} & \quad (d)\;3.125 \times 10^{14} \end {array}\]

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$ (a)\;3.125 \times 10^{13}$
answered Nov 7, 2013 by pady_1

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