Browse Questions

# Find an anti derivative(or integral)of the function by the method of inspection $e^{2x}$

Toolbox:
• $\frac{d}{dx}[F(x)+c]=f(x),$
• $\int f(x)\;dx=F(x)+c$
We know that $\frac{d}{dx}(e^{2x})=2e^{2x}.$

$e^{2x}=\frac{1}{2}\frac{d}{dx}(e^{2x}).$

$\quad\;=\frac{d}{dx}\big(\frac{1}{2}e^{2x}\big).$

Therefore an anti derivative of $e^{2x}$ is $\frac{1}{2}e^{2x}$.