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Home  >>  CBSE XII  >>  Math  >>  Integrals

Find an anti derivative(or integral)of the function by the method of inspection $\cos 3x$

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Toolbox:
  • $\frac{d}{dx}[F(x)+c]=f(x),$
  • $\int f(x)\;dx=F(x)+c$
We know that $\frac{d}{dx}(\sin3x)=3\cos3x.$
 
$\cos 3x=\frac{1}{3}\frac{d}{dx}(\sin 3x).$
 
$\qquad\;\;=\frac{d}{dx}\big(\frac{1}{3}\sin 3x\big).$
 
Therefore an anti derivative of $\cos 3x$ is $\frac{1}{3}\sin 3x$.

 

answered Jan 25, 2013 by sreemathi.v
 
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