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The wavelengths of two sound notes in air are $\large\frac{40}{195}\;$$m$ and $\large\frac{40}{193}\;$$m$. Each note produces 9 beats per second separately with a third note of fixed frequency. The velocity of sound in air in m/s is:

\[\begin {array} {1 1} (a)\;360 & \quad (b)\;320 \\ (c)\;300 & \quad (d)\;340 \end {array}\]

1 Answer

(a) 360
answered Nov 7, 2013 by pady_1

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