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A ray of light refracts from medium 1 into a thin layer of medium 2, crosses the layer and is incident at the critical angle on the interface between the medium 2 and 3 as shown in figure. If the angle of incidence of ray is $\theta$, the value of $\theta$ is :

(a) $\sin ^{-1} \bigg(\large\frac{8}{9}\bigg)$

(b) $\sin ^{-1} \bigg(\large\frac{13}{18}\bigg)$

(c) $\sin ^{-1} \bigg(\large\frac{13}{16}\bigg)$

(d) $\sin ^{-1} \bigg(\large\frac{8}{13}\bigg)$

1 Answer

(c) $\sin ^{-1} \bigg(\large\frac{13}{16}\bigg)$
answered Nov 7, 2013 by pady_1
 

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