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A fully charged capacitor has a capacitance $'C'$. It is discharged through a small coil resistance wire, embedded in a block of specific heat $'s'$ and mass $'m'$ under thermally isolated conditions. If the temperature of the block is raised by $'\Delta T$, the potential difference $V$ across the capacitor initially is :

\[\begin {array} {1 1} (a)\;\bigg(\frac{2\;ms\;\Delta T}{C}\bigg)^2 & \quad (b)\;\bigg(\frac{2ms \Delta T}{C}\bigg)^{1/2} \\ (c)\;\bigg(\frac{2\;ms\;\Delta T}{C}\bigg) & \quad (d)\;2\;ms\;\Delta T. C \end {array}\]
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$ (a)\;\bigg(\frac{2\;ms\;\Delta T}{C}\bigg)^2$
answered Nov 7, 2013 by pady_1

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