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In acidic medium, $100\; ml$ of $0.01\;M\;KMnO_4$ solution oxides $100\;ml$ of $H_2O_2$ solution. The volume of $0.01\;M\;KMnO_4$ required to oxidize the same volume of $H_2O_2$ in alkaline medium in ml. is :

\[\begin {array} {1 1} (a)\;\frac{300}{2} & \quad (b)\;\frac{300}{5} \\ (c)\;\frac{500}{3} & \quad (d)\;\frac{500}{2} \end {array}\]
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Answer Option 2
answered Nov 7, 2013 by pady_1

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