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Questions  >>  EAMCET  >>  Chemistry
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Q)

If the length of the unit cell is 5 A, the smallest distance in A between the two neighboring metal atoms in a face center cubic lattice is :

\[\begin {array} {1 1} (a)\;2.50 & \quad (b)\;5.00 \\ (c)\;7.07 & \quad (d)\;3.535 \end {array}\]

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