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The order of $pH$ of $0.200\;M$ solutions of $NH_4NO_3,Na_2CO_3$ is:

(a) $NH_4NO_3 \; < \;Na_2 CO_3 \; <  NaNO_3$

(b) $NH_4NO_3 \; < \; NaNO_3 \; < Na_2 CO_3$

(c) $Na_2CO_3 \; < \; NaNO_3 \; < NH_4 NO_3$

(d) $NaNO_3 \; < \; NH_4NO_3 \; < Na_2 CO_3$

1 Answer

(b) $NH_4NO_3 \; &lt; \; NaNO_3 \; &lt; Na_2 CO_3$
answered Nov 7, 2013 by pady_1
 
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