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For the plane π=2x-3y+4z=5=0 then points A=(1,2,0),B=(1,2,-3) Options 1)li

For the plane π=2x-3y+4z=5=0 then points A=(1,2,0),B=(1,2,-3) Options 1)lie on the same side of π=0 2) lie on the opposite side of π=0 3) lir on the normal side of to π=0 4) lies on the plane

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