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Bond energy of $F_2,Cl_2$ and $Br_2$ follow the order:

(a) F - F > Cl -Cl > Br - Br

(b) Cl - Cl > Br -Br > F -F

(c) Br-Br >Cl -Cl > F-F

(d) Cl - Cl > F -F > Br - Br
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(b) Cl - Cl > Br -Br > F -F
answered Nov 7, 2013 by pady_1
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