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Questions  >>  CBSE XII  >>  Physics  >>  Current Electricity
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Q)

n identical cells each of E and internal resistance r be connected in services The current through load resistance R

$\begin{array}{1 1} (a)\;I= \frac{nE}{R-nr}\\ (b)\;I= \frac{nE}{R+nr} \\ (c)\;I= \frac{nE-R}{nr} \\ (d)\;I=\frac{E}{R+nr} \end{array} $

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A)
Solution :
$(b)\;I= \frac{nE}{R+nr}$
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