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$(1+2x+3x^2)^{10}=a_0+a_1x+a_2x^2+..........+a_{20}x^{20}=>\large\frac{a_2}{a_1}$=

\[\begin {array} {1 1} (1)\;10.5 & \quad (2)\;21 \\ (3)\;10 & \quad (4)\;5.5 \end {array}\]

1 Answer

$ (1)\;10.5 $
answered Nov 7, 2013 by pady_1
 

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