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$ \large \frac{3x^2+x+1}{(x-1)^4}=\frac{a}{(x+1)}+\frac{b}{(x-1)^2}+\frac{c}{(x-1)^3}+\frac{d}{(x-1)^4} $$ => \begin{bmatrix} a & b \\ c & d \end{bmatrix} $=

\[\begin {array} {1 1} (1)\;\begin{bmatrix} 3 & 7 \\ 5 & 0 \end {bmatrix} & \quad (2)\;\begin{bmatrix} 0 & 3 \\ 7 & 5 \end {bmatrix} \\ (3)\; \begin{bmatrix} 0 & 7 \\ 3 & 5 \end {bmatrix} & \quad (4)\;\begin{bmatrix} 3 & 5 \\ 7 & 0 \end {bmatrix} \end {array}\]

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$(2)\;\begin{bmatrix} 0 & 3 \\ 7 & 5 \end {bmatrix} $
answered Nov 7, 2013 by pady_1
edited Jan 2, 2014 by meena.p
 

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