logo

Ask Questions, Get Answers

X
 
Home  >>  EAMCET  >>  Mathematics

For $x \in R$, the least value of $\large\frac{x^2-6x+5}{x^2+2x+1}$ is :

\[\begin {array} {1 1} (1)\;-1 & \quad (2)\;-\frac{1}{2} \\ (3)\;-\frac{1}{4} & \quad (4)\;-\frac{1}{3} \end {array}\]

1 Answer

(4) $-\large\frac{1}{3}$
answered Nov 7, 2013 by pady_1
 
...