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EAMCET
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Mathematics
For $x \in R$, the least value of $\large\frac{x^2-6x+5}{x^2+2x+1}$ is :
\[\begin {array} {1 1} (1)\;-1 & \quad (2)\;-\frac{1}{2} \\ (3)\;-\frac{1}{4} & \quad (4)\;-\frac{1}{3} \end {array}\]
jeemain
eamcet
math
2010
q11
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asked
Sep 26, 2013
by
meena.p
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1 Answer
(4) $-\large\frac{1}{3}$
answered
Nov 7, 2013
by
pady_1
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