For $x \in R$, the least value of $\large\frac{x^2-6x+5}{x^2+2x+1}$ is :

Question

\[\begin {array} {1 1} (1)\;-1 & \quad (2)\;-\frac{1}{2} \\ (3)\;-\frac{1}{4} & \quad (4)\;-\frac{1}{3} \end {array}\]

Answer 1

(4) $-\large\frac{1}{3}$