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Home  >>  EAMCET  >>  Mathematics

For $x \in R$, the least value of $\large\frac{x^2-6x+5}{x^2+2x+1}$ is :

\[\begin {array} {1 1} (1)\;-1 & \quad (2)\;-\frac{1}{2} \\ (3)\;-\frac{1}{4} & \quad (4)\;-\frac{1}{3} \end {array}\]

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(4) $-\large\frac{1}{3}$
answered Nov 7, 2013 by pady_1
 
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