logo

Ask Questions, Get Answers

X
 
Home  >>  EAMCET  >>  Mathematics

Let $\alpha \neq 1$ be a real root of the equation $x^3-ax^2+ax-1=0,$ where $a \neq -1 $ is a real number. Then a root of this equation, among the following, is :

\[\begin {array} {1 1} (1)\;\alpha^2 & \quad (2)\;-\frac{1}{\alpha} \\ (3)\;\frac{1}{\alpha} & \quad (4)\;-\frac{1}{\alpha^2} \end {array}\]

1 Answer

$ (3)\;\frac{1}{\alpha}$
answered Nov 7, 2013 by pady_1
 

Related questions

Download clay6 mobile appDownload clay6 mobile app
...
X