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If the system of equations :$(k+1)^3x+(k+2)^3y=(k+3)^3 \;;\;(k+1)x+(k+2)y=k+3\;;\;x+y=1$ is consistent, then the value of $k$ is :

\[\begin {array} {1 1} (1)\;2 & \quad (2)\;-2 \\ (3)\;-1 & \quad (4)\;1 \end {array}\]

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1 Answer

(2) -2
answered Nov 7, 2013 by pady_1
 
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