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If $\omega$ is a complex cube root of unity, then $(x+1)(x+ \omega)(x-\omega-1)=$

\[\begin {array} {1 1} (1)\;x^3-1 & \quad (2)\;x^3+1 \\ (3)\;x^3+2 & \quad (4)\;x^3-2 \end {array}\]

1 Answer

$ (2)\;x^3+1$
answered Nov 7, 2013 by pady_1
 

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