logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  EAMCET  >>  Mathematics
0 votes

The period of $\bigg(\tan \theta -\large\frac{1}{3}$$ \tan ^3 \theta\bigg)\bigg(\large\frac{1}{3}$$-\tan ^2 \theta\bigg)^{-1},$ Where $\tan ^{2} \theta \neq \large\frac{1}{3}$ is :

\[\begin {array} {1 1} (1)\;\frac{\pi}{3} & \quad (2)\;\frac{2\pi}{3} \\ (3)\;\pi & \quad (4)\;2 \pi \end {array}\]

Can you answer this question?
 
 

1 Answer

0 votes
$ (1)\;\frac{\pi}{3}$
answered Nov 7, 2013 by pady_1
 
Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...