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Home  >>  EAMCET  >>  Mathematics
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$a \sin ^2 \theta+ b \cos ^2 \theta=c=>\tan ^2 \theta=$

\[\begin {array} {1 1} (1)\;\frac{b-c}{a-c} & \quad (2)\;\frac{c-b}{a-c} \\ (3)\;\frac{a-c}{b-c} & \quad (4)\;\frac{a-c}{c-b} \end {array}\]
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1 Answer

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$(2)\;\frac{c-b}{a-c}$
answered Nov 7, 2013 by pady_1
 
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