# If $\Delta =a^2-(b-c)^2,$ is the area of the triangle ABC, then $\tan A=$

$\begin {array} {1 1} (1)\;\frac{1}{16} & \quad (2)\;\frac{8}{15} \\ (3)\;\frac{3}{4} & \quad (4)\;\frac{4}{3} \end {array}$

$(2)\;\frac{8}{15}$
answered Nov 7, 2013 by