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If $\Delta =a^2-(b-c)^2, $ is the area of the triangle ABC, then $\tan A=$

\[\begin {array} {1 1} (1)\;\frac{1}{16} & \quad (2)\;\frac{8}{15} \\ (3)\;\frac{3}{4} & \quad (4)\;\frac{4}{3} \end {array}\]

1 Answer

$(2)\;\frac{8}{15} $
answered Nov 7, 2013 by pady_1
 
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