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If $\Delta =a^2-(b-c)^2, $ is the area of the triangle ABC, then $\tan A=$
\[\begin {array} {1 1} (1)\;\frac{1}{16} & \quad (2)\;\frac{8}{15} \\ (3)\;\frac{3}{4} & \quad (4)\;\frac{4}{3} \end {array}\]
jeemain
eamcet
math
2010
q28
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Sep 26, 2013
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meena.p
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$(2)\;\frac{8}{15} $
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Nov 7, 2013
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pady_1
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