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Home  >>  EAMCET  >>  Mathematics
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In a triangle $ABC,C=90^{\circ}$.Then $\large\frac{a^2-b^2}{a^2+b^2}=$

\[\begin {array} {1 1} (1)\;\sin (A+B) & \quad (2)\;\sin (A-B) \\ (3)\;\cos (A+B) & \quad (4)\;\cos (A-B) \end {array}\]

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$ (2)\;\sin (A-B)$
answered Nov 7, 2013 by pady_1
 
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