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Let $\overrightarrow {a}=\overrightarrow {i}- 2 \overrightarrow {j}+ 3 \overrightarrow {k},\; \overrightarrow {b}=2 \overrightarrow {i}+3 \overrightarrow {j}-\overrightarrow {k}$ and $\overrightarrow {c}= \lambda \overrightarrow {i}+\overrightarrow {j}+(2 \lambda -1) \overrightarrow {k}.$ If $\overrightarrow {c}$ is parallel to the plane containing $\overrightarrow {a},\overrightarrow {b} $ then $\lambda=$

\[\begin {array} {1 1} (1)\;0 & \quad (2)\;1 \\ (3)\;-1 & \quad (4)\;2 \end {array}\]

1 Answer

(a) 0
answered Nov 7, 2013 by pady_1
 

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