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If the coefficients of $2^{nd},3^{rd}\:and\:4^{th}$ terms in the expansion of $(1+x)^{2n} $ are in A.P., then $n=?$

$\begin{array}{1 1} 1 \\ \frac{5}{2} \\ \frac{7}{2} \\ No\;such\;n\;exists \end{array} $

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Given: $^{2n}C_1,^{2n}C_2, ^{2n}C_3$ are in A.P.
But since $n$ cannot be 1 $n=\large\frac{7}{2}$
answered Oct 1, 2013 by rvidyagovindarajan_1

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