$3x + 2y = \frac{1}{5}$ and $3x - 2y = \frac{2}{5}$, then $\frac{y}{x}$ is

Question

$\begin{array}{1 1} (a)\; \frac{-1}{2} \\ (b) \frac{1}{2} \\ (c)\; -2 \\ (d)\; 2 \end{array}$