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Suppose that a random variable X follows Poisson distribution. If $P(X=1)=P(X=2)$ then $P(X=5)=$

\[\begin {array} {1 1} (1)\;\frac{2}{3}e^{-2} & \quad (2)\;\frac{3}{4}e^{-2} \\ (3)\;\frac{4}{15}e^{-2} & \quad (4)\;\frac{7}{8}e^{-2} \end {array}\]

1 Answer

$(3)\;\frac{4}{15}e^{-2}$
answered Nov 7, 2013 by pady_1
 

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