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If a straight line L is perpendicular to the line $4x-2y=1$ and forms a triangle of area 4 square units with the coordinate axes, then an equation of the line L is :

\[\begin {array} {1 1} (1)\;2x+4y+7=0 & \quad (2)\;2x-4y+8=0 \\ (3)\;2x+4y+8=0 & \quad (4)\;4x-2y-8=0 \end {array}\]
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(3) 2x+4y+8=0
answered Nov 7, 2013 by pady_1

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