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EAMCET
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Mathematics
A pair of perpendicular lines passes through the origin and also through the points of intersection of the curve $x^2+y^2 =4$ with $x+y=a,$ where $a > 0$. Then $a=$
\[\begin {array} {1 1} (1)\;2 & \quad (2)\;3 \\ (3)\;4 & \quad (4)\;5 \end {array}\]
jeemain
eamcet
math
2010
q47
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Sep 27, 2013
by
meena.p
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Nov 7, 2013
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pady_1
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