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If $3x^2-11xy+10y^2-7x+13y +k=0$ denotes a pair of straight lines, then the point of intersection of the lines is :
\[\begin {array} {1 1} (1)\;(1,3) & \quad (2)\;(3,1) \\ (3)\;(-3,1) & \quad (4)\;(1,-3) \end {array}\]
jeemain
eamcet
math
2010
q48
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Sep 27, 2013
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meena.p
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(2) (3,1)
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Nov 7, 2013
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pady_1
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