If $3x^2-11xy+10y^2-7x+13y +k=0$ denotes a pair of straight lines, then the point of intersection of the lines is :
$\begin {array} {1 1} (1)\;(1,3) & \quad (2)\;(3,1) \\ (3)\;(-3,1) & \quad (4)\;(1,-3) \end {array}$