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If $3x^2-11xy+10y^2-7x+13y +k=0$ denotes a pair of straight lines, then the point of intersection of the lines is :

\[\begin {array} {1 1} (1)\;(1,3) & \quad (2)\;(3,1) \\ (3)\;(-3,1) & \quad (4)\;(1,-3) \end {array}\]

1 Answer

(2) (3,1)
answered Nov 7, 2013 by pady_1
 
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