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The equation of the radical axis of the pair of circles $7x^2+7y^2-7x+14y+18=0$ and $4x^2+4y^2-7x+8y+20=0$ is :

\[\begin {array} {1 1} (1)\;x-2y-5=0 & \quad (2)\;2x-y+5=0 \\ (3)\;21x - 68=0 & \quad (4)\;23x- 68=0 \end {array}\]

1 Answer

(3) 21x-68=0
answered Nov 7, 2013 by pady_1
 
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