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If the lengths of tangents drawn to the circles :$x^2+y^2-8x+40=0; 5x^2+5y^2-25x+80=0;x^2+y^2-8x+16y+160=0$ from the point P are equal, then P=

\[\begin {array} {1 1} (1)\;\bigg(8,\frac{15}{2}\bigg) & \quad (2)\;\bigg(-8, \frac{15}{2}\bigg) \\ (3)\;\bigg(8,\frac{-15}{2}\bigg) & \quad (4)\;\bigg(-8,\frac{-15}{2}\bigg) \end {array}\]

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$ (3)\;\bigg(8,\frac{-15}{2}\bigg)$
answered Nov 7, 2013 by pady_1
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