If $i =\sqrt{-1}$, what can be the value of $\dfrac{(3+i)(2-i)}{3-i }$ is
$\begin{array}{1 1} (a)\; \dfrac{7+i}{5} \\ (b)\; \dfrac{7-i}{5} \\ (c)\; \dfrac{i-7}{5} \\ (d)\; \dfrac{-i-7}{5} \end{array}$