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The equation of the circle concentric with the circle $x^2+y^2-6x+12y+15=0$ and of double its area is :
\[\begin {array} {1 1} (1)\;x^2+y^2-6x+12y-15=0 & \quad (2)\;x^2+y^2-6x+12y-30=0 \\ (3)\;x^2+y^2-6x+12y-25=0 & \quad (4)\;x^2+y^2-6x+12y-20=0 \end {array}\]
jeemain
eamcet
math
2010
q51
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Sep 27, 2013
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meena.p
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$ (1)\;x^2+y^2-6x+12y-15=0$
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Nov 7, 2013
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pady_1
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