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Let M be the foot of the perpendicular from a point P on the parabola $y^2=8(x-3)$ onto its directrix and let S be the focus of the parabola. If $\Delta SPM$ is an equilateral triangle, then $P=$

\[\begin {array} {1 1} (1)\;(4 \sqrt 3,8) & \quad (2)\;(8. 4\sqrt 3) \\ (3)\;(9,4 \sqrt 3) & \quad (4)\;(4 \sqrt 3,9) \end {array}\]

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$(3)\;(9,4 \sqrt 3)$
answered Nov 7, 2013 by pady_1
why u all guys just  post answers......cant u send solutions......answers can be found at the back of the book...if you know method  pls post

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