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Home  >>  EAMCET  >>  Mathematics
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If the lines $2x+3y+12=0,x-y+k=0$ are conjugate with respect to the parabola $y^2=8x,$ then $k=$

\[\begin {array} {1 1} (1)\;10 & \quad (2)\;\frac{7}{2} \\ (3)\;-12 & \quad (4)\;-2 \end {array}\]
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$(3) -12$
answered Nov 7, 2013 by pady_1
 
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